For x6 0 and some xed p p x 02 ax2 p2 p x x2 ax2 p2 x2 4apx2 1 4ap since x 6 0 1 4p a. Derivation of Quadratic Formula. Ax 2 bx c x -b2a Finding the X Coordinate of the Vertex.
If latexlefta0rightlatex is a vertex of the hyperbola the distance from latexleft-c0rightlatex to latexlefta0rightlatex is latexa-left-crightaclatex.
P - and we get the following equation. Now I also dont know the proof but I proved it by using some Common Sense. Substitute the values for a and b. The vertex is also the equations axis of symmetry.