So the first one is the limit as x approaches 3 of f of x minus f of 3 over x minus 3. Now we get lim x2 x2 22 4. Here is an example.
Write the expression replacing every x with x Dx.
So for the posted function we have fxlim_hrightarrow0mxhb-mxbh By multiplying out the numerator lim_hrightarrow0mxmhb-mx-bh By cancelling out mx s and b s lim_hrightarrow0mhh. So lets think about x minus-- x equals 3 is right over here. Displaystyle mathbf y t y_ 1 tldots y_ n t if the limit exists. With the graph of the function f as an aid evaluate the following limits.