764gC2H3Br3 1molC2H3Br3 26672 gC2H3B3 0286molC2H3Br3491gO2. The equation is already balanced with the relationship4 mol C 2H 3Br 3 to 11 mol. Also we never get all of the products that we thought we mig.
The percent yield is the ratio of the actual yield to the theoretical yield expressed as a percentage.
Multiply by 100 to convert to a percentage. Theoretical yield H 2 O 150 mol H 2 O. Chemistry doesnt always work perfectly silly. Divide the number of millimoles of each reagent by the stoichiometric factor for that reagent.