Either youll be provided with one point on the line and the slope of the line or youll be provided two points on the line. Y y 1 m x x 1 y 3 2 2 x p 6 Answer. 02 normalofyfrac x afrac a xxfrac a 2 normalofyx42x.
Y 3x 2.
02 normalofyfrac x afrac a xxfrac a 2 normalofyx42x. Using the slope formula set the slope of each normal line from 3 15 to. Y - 8 -112 x - 2 hence the equation of the normal at 28 is 12y x 98. And solve for x.